A solution containing 1.50 mM ethanol and 2.40 mM methanol gave peak areas of 1487 and 3544, respectively. Subsequently, 2.00 mL of 3.2 mM methanol was added to a 7.00 mL unknown ethanol and diluted to 10.00 mL. The final solution gave peak areas of 6235 and 4487 for ethanol and methanol, respectively. Calculate the concentration of ethanol in the original unknown.

According to the diagram; a) identify the anode of the cell and write the half-reaction that occurs there b) write the overall equation for the reaction that occurs as the cell operates c) calculate the value of the standard cell potential ,e cell. d)write the shorthand notation of the cell above e)indicate the flow of the electrons on the diagram

Which ocean zone has the most abundant primary producer and why a) the abyssopelagic zone ,du to the absence of light and cold water temperatureb) the bathypelagic zone, due to the absence of light and cold water temperaturec) the mesopelagic zone ,due to uts high light availability and warm water temperature d) the epipelagic zone, due to its high light availability and warm water temperature

When balancing a chemical equation: