For the balanced equation shown below, how many moles of N2 will react with 0.3034 moles of Mg? 3 Mg + N2 Mg3N2

Round answer to 4 sig-figs.

0.1011 moles of N₂

Explanation:

This is the reaction:

3 Mg + N₂ → Mg₃N₂

3 moles of magnesium can react to 1 mol of nitrogen in order to produce 1 mol of magnesium nitride.

We can solve this by a rule of three:

3 mol of Mg need 1 mol of N₂ for the reaction

Then, 0.3034 moles of Mg may react to (0.3034 . 1) / 3 = 0.1011 moles of nitrogen.

The stoichiometry is 3:1