How many grams of MgBr2 are needed to create 3.0L of a 4.5M aqueous solution of magnesium bromide?

2486 g

Explanation:

First we calculate how many moles of MgBr₂ are required to create such a solution, using the definition of molarity and the given volume and concentration:

Molarity = moles / liters4.5 M = moles / 3.0 Lmoles = 4.5 M * 3.0 L = 13.5 mol

Now we convert 13.5 moles of MgBr₂ into grams, using its molar mass:

13.5 mol * 184.113 g/mol = 2486 g

Firstly, the water in the dams hold gravitational potential energy as they are above ground level. the gravitational potential energy is then transferred to kinetic energy as it falls, spinning the turbinethe turbine then spins the generator, which is a large magnet surrounded by metal coils. by doing this, the generator generates electricity. in this action, the energy transfer taken place is kinetic to electric energy

Answerhund's rule;