Give the hybridization for the C in HCN

Explanation:

In HCN,

Carbon is singly - bonded ( 1 sigma bond ) to Hydrogen while triply - bonded ( 1 sigma, 2 pi bonds) to Nitrogen.

Thus, the Stearic No. for Carbons is:

= No. of sigma bonds + No. of lone pairs

= 2 + 0

= 2

According to Stearic No.:

=> sp = 2

=> sp² = 3

=> sp³ = 4

Hence,

The hybridization of C in HCN is sp.

Hope this helped!

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.