sulphur has 2 naturally occurring isotopes: 94.99% of mass number 32 5.01% of mass number 34 calculate the relative atomic mass of sulphur. give your answer to 1 decimal place

Consider the reaction: 2al(s) + fe2o3(s) → al2o3(s) + 2fe(s) the δhf for fe2o3(s) = -824.3 kj/mole. the δhf for al2o3(s) = -1675.7 kj/mole. finish the equation. δhrxn = [(1)( kj/mole) + (2)( kj/mole)] - [(1)( kj/mole) + (2) ( kj/mole)]