35 POINTS Consider the following reaction:
4P + 502 → P4010
The percent yield of P4010 when 6.20 g of phosphorus burns in
excess oxygen is 67.0 %.What is the actual yield of P4010?
(Molar mass of P = 31.0 g/mol, molar mass of P4010 = 284
g/mol) (Round your answer 3 significant figures e. g. 5.62)
grams

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the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

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