A gas at 65°C occupies 4.0 L. At what temperature will the volume be 3.0 L?

253.5 K

Explanation:

Charles law equation, which is as follows is used to solve this question:

V1/T1 = V2/T2

Where;

V1 = initial volume (Litres)

V2 = final volume (Litres)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the numerical information provided in this question:

V1 = 4.0 L

V2 = 3.0 L

T1 = 65°C = 65 + 273 = 338K

T2 = ?

Using V1/T1 = V2/T2

V1T2 = V2T1

T2 = V2 × T1/V1

T2 = 3 × 338/4

T2 = 1014/4

T2 = 253.5 K

the temperature of the gas, in k, not celsius.