Balance the equation below for the reaction, using the smallest whole number coefficients __Al(s)+__CuSO4(aq)—>__Al2(SO4)3 (aq)+__Cu(s)

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Explanation:

2Al⁰(s) + 3CuSO₄(aq) => Al₂(SO₄)₃(aq) + 3 Cu(s)

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                1 mole = 1 N₀ = 6.023 x 10²³ particles = 1 formula weight

        Vol H₂(g) = 3 moles x 22.4 L/mole = 67.2 Liters H₂(g)

        Vol N₂(g) = 1 moles x 22.4 L/mole = 22.4 Liters N₂(g)  

        Vol NH₃(g) = 2 moles x 22.4 L/mole = 44.8 Liters NH₃(g)

         moles => coefficient values

         equation masses => coefficient x formula wt. (grams)

          particle numbers => coefficient x Avogadro's No. (=6.023 x 10²³)

          gas volumes => coefficient x 22.4 Liters

          molar energy values => Equation heat of rxn/coefficient

Yeah, I get carried away at times. Hope this will be useful. :-)

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.

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