Consider the following intermediate chemical equations. C(s) + O2(g) → CO2(g) AH, = -393.5 kJ 2CO(g) + O2(g) → 2C02(g) AH2 =-566.0 kJ 2H2O(g) → 2H2(g) + O2(g) AH, = 483.6 kJ The overall chemical equation is C(s) + H2O(g) → CO(g)+ H2(g). To calculate the final enthalpy of the overall chemical equation, which step must occur? Reverse the first equation, and change the sign of the enthalpy. Then, add.

Reverse the second equation, and change the sign of the enthalpy. Then, add.

Multiply the first equation by three, and triple the enthalpy. Then, add.

Divide the third equation by two, and double the enthalpy. Then, add.​

the answer is either b or c

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

diaria maybe go see a doctor about that