How many grams are 3.01 x 10^23 molecules of methane

One mole of any gas at STP takes up 22.4 L of volume.

one mole of gas = 22.4 L (a)

one mole of gas has 6.02 x

10

23

particles( Molecules) (b)

equating (a) and (b) we get

6.022 x

10

23

particles (Molecules) = 22.4 L

Making conversion factors 22.4 L / 6.02 x

10

23

particles or

6.02 x

10

23

particles / 22.4 L

since we want change the # of molecules into L we will use the conversion factor that when multiplied by the given number

gives L as the final unit.

3.01 x

10

23

particles x 22.4 L / 6.02 x

10

23

particles

11.2 L

the answer is 75.0%.