What will the volume of 254 cm3 of gas be at STP if its original temperature is 72.6° C?

200.6cm³

Explanation:

Using Charles law equation as follows:

V1/T1 = V2/T2

Where;

V1 = initial volume (cm³)

V2 = final volume (cm³)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the question;

initial volume (V1) = 254cm³

final volume (V2) = ?

Initial temperature (T1) = 72.6°C = 72.6 + 273 = 345.6K

Final temperature (T2) = 273K

V1/T1 = V2/T2

254/345.6 = V2/273

Cross multiply

345.6 × V2 = 273 × 254

345.6V2 = 69342

V2 = 69342 ÷ 345.6

V2 = 200.6cm³

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