NH3(g) + HCl(g) = NH4Cl(s)
During an experiment, 16.00 g of solid NH4Cl was added to a 500.0
...
NH3(g) + HCl(g) = NH4Cl(s)
During an experiment, 16.00 g of solid NH4Cl was added to a 500.0
mL flask at 25.0°C. The equilibrium constant for this reaction at this
temperature is 8.9 x 10^15, determine the partial pressures (in atm) of
NH3 and HCl after the reaction reaches equilibrium.
Answers: 3
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