What is the molality of 151 grams of na2so4 dissolved in 547 g of water?

Molar mass Na2SO4 => 142.04 g/mol

Number of moles:

n = sample mass / molar mass

n = 151 / 142.04 => 1.063 moles

Mass of solvent in kilograms :

1 kg = 1000 g

574 g / 1000 = 0.574 kg

Therefore:

b = n solute / m solvent

b = 1.063 / 0.547

b = 1.943 mol/kg

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

Firstly, the water in the dams hold gravitational potential energy as they are above ground level. the gravitational potential energy is then transferred to kinetic energy as it falls, spinning the turbinethe turbine then spins the generator, which is a large magnet surrounded by metal coils. by doing this, the generator generates electricity. in this action, the energy transfer taken place is kinetic to electric energy