Use coulomb's law to calculate the ionization energy in kj/mol of an atom composed of a proton and an electron separated by 185.00 pm .

Energy = 752.88 kJ/mol

Explanation:

The force of attraction can be written as:

Integrating to find the expression for energy. We get that:-

Where,  

K is the Coulomb's constant having value 9×10⁹ N. m²/C²

 is the charge on the cation

 is the charge on the anion

e is electronic charge = Charge of the electron = Charge on proton

r is the distance between the cation and anion  = 185.00 pm

Also, 1 pm = 10⁻¹² m

So, r = 185×10⁻¹² m

Applying in the equation,  

Also,

1 atom =

So,

Energy =

Also, 1 J = 0.001 kJ

So, Energy = 752.88 kJ/mol

1 is the answer to this problem

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol