What is the chemical formula for propane?
C38H
3C8H
C3H8
3CH8

The data below were determined for the reaction shown below. s2o82– + 3i – (aq) → 2so42– + i3– expt. # [s2o82–] (m) [i –] (m) initial rate 1 0.038 0.060 1.4 × 10 – 5 m/s 2 0.076 0.060 2.8 × 10 – 5 m/s 3 0.076 0.030 1.4 × 10 – 5 m/s the rate law for this reaction must be:

The combustion of methane, ch4, releases 890.4kj/mol. that is, when one mole of methane is burned,890.4 kj are given off to the surroundings. this meansthat the products have 890.4 kj less than the reactants. thus, ah for the reaction = - 890.4 kj. a negative symbolforah indicates an exothermic reaction. ch (g) + 20 (g)> co2 (g) + 2 h0 (1); ah = - 890.4 kga) how much energy is given off when 2.00 mol of ch, are burned? b) how much energy is released when 22.4g of ch. areburned?

What would happen if no were added to n(g)+o2=2no(g) at equilibrium?