Lithium forms ions with a charge of lt Oxygen forms ions with a charge of 2- in the ionic compound lithium oxide, how many atoms of lithium will there be if there is 1 atom of oxygen?
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There are 2 lithium atoms in the ionic compound lithium oxide, Li₂O

Explanation:

The charge of ions formed by lithium = 1⁺

The charge of ions formed by oxygen = 2⁻

In the ionic compound lithium oxide having 1 atom of oxygen, we have;

For the compound to be electronically neutral, the sum of the charges of the atoms in the ionic compound is zero

The charge of 1 atom of oxygen in the lithium oxide compound + The charge of the 'n' number of lithium atoms in the lithium oxide compound = 0

∴ 2⁻ + n × 1⁺ = 0

n × 1⁺ = 0 - 2⁻ = 2⁺

n = 2⁺/(1⁺) = 2

n = 2

The number of lithium atoms in the lithium oxide compound, n = 2

Therefore, there are two lithium atoms in the ionic lithium oxide (Li₂O) compound

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

i wish i could but this one is weird give me abc and i can solve it.