Chemistry, 04.03.2021 03:30 yalley1982

6 Na(s) – Al2(SO4)3(aq) => 3 Na2SO4(aq) + 2 Al(s) If 3.00 moles of aluminum sulfate are reacted with excess sodium, 150.1
grams of aluminum are produced. What is the percent yield of this
reaction?

Answers: 3

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6 Na(s) – Al2(SO4)3(aq) => 3 Na2SO4(aq) + 2 Al(s) If 3.00 moles of aluminum sulfate are reacted...