Calculate the mass of 1 Mole of Copper(ii) sulfate pentahydrate​

200 g CuSO₄ · 5H₂O

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Organic

Reactions

Stoichiometry

Step 1: Define

[Given] 1 mol CuSO₄ · 5H₂O (Copper II sulfate pentahydrate)

Step 2: Identify Conversions

[PT] Molar Mass of Cu - 63.55 g/mol

[PT] Molar Mass of S - 32.07 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CuSO₄ - 63.55 + 32.07 + 4(16.00) = 159.62 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Convert

There is 5 moles of water added for every one mole of Copper II Sulfate present.

Step 4: Check

Follow sig fig rules and round. We are given 1 sig fig.

249.72 g CuSO₄ · 5H₂O ≈ 200 g CuSO₄ · 5H₂O

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