Calculate AH® for the following: CH (8) + Ch() - CC1(0) + HC1) (unbalanced]
AH ICH (2) = -74.87 kJ/mol
AH CCl4(e)) = -96.0 kJ/mol
all ICCI(0) = -1.39 kJ/mol
AHHCUC)] = -92.31 kl/mol
AHHICK(04)) = -167.46 kJ/mol
SHICH2)) = 1210 kJ/mol

For a research project, a student decided to test the effect of the lead(ii) ion (pb2+) on the ability of salmon eggs to hatch. this ion was obtainable from the water‐soluble salt, lead(ii) nitrate, which the student decided to make by the following reaction. pbo(s) + 2 hno3(aq) → pb(no3)2(aq) + h2o losses of product for various reasons were expected, and a yield of 86.0% was expected. in order to have 5.00 g of product at this yield, how many grams of pbo should be reacted? (assume that sufficient nitric acid, hno3, would be used.)