Given a formula of a functional group: An organic compound that has this functional group is classified as A) an acid, B) an aldehyde, C) an ester, D) a ketone

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there are about seven isomers of c4h10o

explanation:

we know from the formula that these isomers contain no rings or double bonds.

the isomers must be alcohols and ethers.

let's start by drawing the alcohols.

start with four carbons in a row and put an   "oh" group in every possible position.

this gives us :

( note that all these 3's and 2's are supposed to come down not up)

1.ch ³ch²ch²ch²oh, butan 1-ol  

2. ch³ch²ch(oh)ch³, butan 2-ol

now use a 3-carbon chain with a   ch ³ on the middle carbon.

this gives us :

1. (ch³)²chch²oh, 2-methylpropan-1-ol

2. (ch³)³coh 2-methylpropan-2-ol.

now for the ethers.

let's start with five atoms in a row.

this gives us :

1.ch³ch²och²ch³, ethoxyethane

finally, the only choice for a branched-chain ether is

2. (ch³)²choch³, 2-methoxpropane.

and there are your seven isomers of c4h10o