For the same reaction above, if 32 grams of AlCl3 is combined with excess AgNO3, how many grams of AgCl can be made

103.2 g of AgCl can be made in the reaction

Explanation:

We state the reaction to analyse the problem:

AlCl₃ + 3AgNO₃ →  3AgCl  +  Al(NO₃)₃

We convert the mass of chloride to moles:

32 g . 1mol/ 133.34g = 0.240 moles

Ratio is 1:3. See the stoichiometry

1 mol of aluminum chloride can produce 3 moles of AgCl

Then, 0.240 will produce (0.240 . 3)/1= 0.720 moles.

We convert the moles to mass: 0.720 mol . 143.32g/1mol = 103.2 g

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

sry but any answer choices