3. How many grams of O2 will be produced from 14.00 moles of NaClO,?
2 NaClO3 → 2 NaCl + 3 O2

How many grams of
O
2
are produced if 12.00 moles of
N
a
C
l
O
3
?
We begin with a balanced chemical equation that is provided in the question.
2
N
a
C
l
O
3
→
2
N
a
C
l
+
3
O
2
Next we determine what we have and what we want.
We have 12.00 moles of
N
a
C
l
O
3
and we want grams of
O
2
.
We set up a roadmap to solve the problem
m
o
l
N
a
C
l
O
3
→
m
o
l
O
2
→
g
r
a
m
s
O
2
We need the molar mass (
g
f
m
) of
O
2
.
O
2
= 32.0 g/mol
We need the mole ratio between
N
a
C
l
O
3
:
O
2
2:3. This comes from the coefficients of the balanced chemical equation.
Now we set up conversion factors following the roadmap from above.
Unit we want in the numerator, unit to cancel in the denominator.
12.00
m
o
l
N
a
C
l
O
3
x
3
m
o
l
O
2
2
m
o
l
N
a
C
l
O
3
x
32.0
.
g
O
2
1
m
o
l
O
2
=
Multiply the numerators, and divide the denominators.
The outcome is
576.0
g
O
2

will be produced from 12.00 moles
N
a
C
l
O
3
I hope this was helpful.

The answer is nitrogen-containing bases