1) If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

204.8 K

Explanation:

We use the ideal gas equation:

PV = nRT

where R is the gas constant (0.082 L.atm/K.mol).

We have the following data:

n= 4 moles

P = 5.6 atm

V = 12 L

So, we introduce the data in the ideal gas equation to calculate the temperature (T):

T = PV/nR = (5.6 atm x 12 L)/(4 mol x 0.082 L.atm/K.mol) = 204.8 K ≅ -68 °C

what's the

it would be a gas formation