Stoichiometry: You conduct the following precipitation reaction in a lab:
CoCl₂ + 2NaOH → 2NaCl + Co(OH)₂
If you react 10.0 mL of 1.5 M CoCl₂ with plenty of NaOH, how many grams of Co(OH)₂ will precipitate out?

1.4 g Co(OH)₂

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Unit 0

Atomic Structure

Aqueous Solutions

Stoichiometry

Step 1: Define

[RxN - Balanced] CoCl₂ + 2NaOH → 2NaCl + Co(OH)₂

[Given] 10.0 mL, 1.5 M CoCl₂

[Solve] grams Co(OH)₂

Step 2: Identify Conversions

[Base 10] 1000 mL = 1 L

[RxN] 1 mol CoCl₂ → 1 mol Co(OH)₂

[PT] Molar Mass of Co - 58.93 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of Co(OH)₂ - 58.93 + 2(16.00) + 2(1.01) = 92.95 g/mol

Step 3: Stoich

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs as our lowest.

1.39425 g Co(OH)₂ ≈ 1.4 g Co(OH)₂

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

i think it's c. i'm not sure but i think so.