Consider the following reaction where Kp = 0.365 at 1150 K: 2502(g) + O2(g) =2503(g)
If the three gases are mixed in a rigid container at 1150 K so that the partial pressure of each gas is initially one atm, what will happen?
Indicate True (I) or False (F) for each of the following:
1. A reaction will occur in which SO3() is produced.
2. K, will increase
✓ 3. A reaction will occur in which S02 is produced.
4. Q is less than K
5. The reaction is at equilibrium. No further reaction will occur.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

the answer to your question is c

b) nuclear ive learned that in a pedtrodic table

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally