Rank the following 3rd period atoms in order of increasing Radius (size). Sodium, silicon, magnesium, sulfur, argon

A. magnesium, sulfur, argon, sodium, silicon
B. sodium, magnesium, silicon, sulfur, argon
C. Sodium, silicon, magnesium, sulfur, argon
D. argon, sulfur, silicon, magnesium, sodium

Need the answer only plz thank you:)

Woah that’s a lot to read xd i’ll try though. i’ll get back t you if. i know the andwer

The problem here is that according to aufbau principle before 3d orbital 4s subshell comes.after filling 3p orbital with electrons you have 4 electrons left, you place two in 4s with opposite spin and the other two in 3d in any of its two orbitals of total five orbitals with the same spin.

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na