Determine the maximum number of electrons in an atom with the following quantum nurnbers: (a)=4 and 1= 1. (b) n = 3,1 = 2 and m = -1. (e) n = 4, 1 = 2, m = 0 and m,
2 (d) n=3,1 = 1, and m = -1, (e) n = 3 and 1 = 2.​

what does the table look like

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2