What the the noble gas configuration for Boron

[He]23

Explanation:

The electron configuration for Boron is 123, but you can also write it as the noble gas configuration, which is [He]23

Note that helium has the configuration of 1, so we instead of writing it, we write [He]. This can be useful when writing the configurations of elements from the later periods as it saves space.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :