What would the [OH-] of a solution that has a pOH of 2.7 be?

The [OH⁻] of a solution that has a pOH of 2.7 will be 2*10⁻³

Explanation:

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.

pOH indicates the concentration of hydroxyl ions [OH-] present in a solution. In this way, pOH is defined as the negative logarithm of the activity of hydroxide ions, that is, the concentration of OH- ions:

pOH= -log [OH⁻]

In this case, pOH has a value of 2.7. Replacing:

2.7= -log [OH⁻]

and solving:

[OH⁻]=10⁻² ⁷

you get:

[OH⁻]≅ 2*10⁻³

The [OH⁻] of a solution that has a pOH of 2.7 will be 2*10⁻³

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