1) In this experiment, you will be mixing aqueous solutions of sodium carbonate and calcium chloride to produce solid calcium carbonate. Na CO2 (aq) +CaCl(aq) — 2 NaCl(aq) +CaCO3
Order the steps required to predict the volume (in mL) of 0.200 M sodium carbonate needed to produce 2.00 g of calcium carbonate. There is an excess of calcium chloride.
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Step 1
Convert mass of calcium carbonate 10 moles of calcium carbonate
Step 2
Compare moles of calcium carbonate to moles of sodium carbonate based on balanced equation to calculate moles of sodium carbonate required
Step 3
Compute the volume of sodium carbonate solution required
Step 4
Convert the volume of sodium carbonate solution required from liters to milliers
2) Na2CO3(aq) + CaCl2(ag) + 2NaCl(aq) + CaCO3(-)
Calculate the volume (in mL) of 0.200 M Na2CO, needed to produce 2.00 g of CaCO3(s). There is an excess of CaCl.
Molar mass of calcium carbonate = 100.09 g/mol
Volume of sodium carbonate - 100 mL
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