a graduated cylinder is filled to the 40.00 ml mark with mineral oil. The masses of the cylinder before and after the addition of mineral oil are 124.966g and 159.446g. In the seperate experiment, a metal ball bearing of mass 18.713g is placed in the cylinder and the cylinder is again filled to the 40.00ml mark with the mineral oil. The combined mass of the ball bearing and mineral oil is 50.952g. calculate the density of the ball bearing

7.30 g/mL

Explanation:

First we calculate the density of the mineral oil with the data from the first experiment:

Regarding the second experiment, we can express the volumes as follows:

We can calculate the mass of oil using the given sum of masses:

We input the data we know in the volume equation:

And solve for the density of the ball:

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%