Chemistry, 15.02.2021 22:10 marandahuber
N2+3H2=>>2NH3. If 6.72dm³ of each of Nitrogen and hydrogen (measured at S. T.P.) are made to produced Ammonium. Which of the reacted will be in excess and by how many moles?
Answers: 3
= 22, 4 l/mol
) = 6,72 
= 6,72 l
) = 6,72 
(we have more hydrogen than is need for the reaction)
= 0,1 mol (
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N2+3H2=>>2NH3. If 6.72dm³ of each of Nitrogen and hydrogen (measured at S. T.P.) are made to p...
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