The vapor pressure of liquid hexane, C_6 H_14, is 40.0 mm Hg at 271 K. A sample of C_6 H_14 is placed in a closed, evacuated container of constant volume at a temperature of 400 K. It is found that all of the C_6 H_14 is in the vapor phase and that the pressure is 74.0 mm Hg. If the temperature in the container is reduced to 271 K, which of the following statements are correct? Choose all that apply. a) Liquid hexane will be present. b) Some of the vapor initially present will condense. c) Only hexane vapor will be present. d) No condensation will occur. e) The pressure in the container will be 50.1 mm Hg.

Only Options (c), (d) and (e) are correct.

Explanation:

Without mincing words let's dive straight into the solution to the question above.

The following parameters from the question are given below which are going to aid in solving this question.

=> The vapor pressure of liquid hexane = 40.0 mmHg, Temperature, T1 = 271K.

=> The temperature, T2 = 400 K, the pressure,P2 = 74.0 mm Hg. The reduced temperature,T3 in the container = 271 K.

What is needed now is to Determine the final temperature, T3 = 271/400 × 74 = 50.01 mmHg.

Therefore, we only have the presence of the vapour of Hexane and there is no condensation. Hence, option c, d and e are the only correct options.

the transfer of heat by electromagnetic radiation is called thermal radiation . it is usually carried out by electromagnetic waves in an energy range just below the visible spectrum, which is the infrared range.

so the answer would be radiation.

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