A bullet seized from a crime scene has a composition of lead 11.6 g, tin 0.5 g, and antimony 0.4 g. What is the percentage of lead in the bullet? Express your answers to
the ones place.

92.8%

Explanation:

Step 1: Given data

Step 2: Calculate the total mass of the bullet

The total mass of the bullet is equal to the sum of the masses of the elements that form it.

m = mPb + mSn + mSb = 11.6 g + 0.5 g + 0.4 g = 12.5 g

Step 3: Calculate the mass percentage of Pb in the bullet

We will use the following expression.

%Pb = mPb / m × 100%

%Pb = 11.6 g / 12.5 g × 100% = 92.8%

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

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