the grams of barium that are in 2.3 x 10^23 atoms of barium is 52.4 g (answer c)
calculation
mass = moles of ba x molar mass of ba
molar mass of ba from periodic table= 137.3 g/mol
use the avogadro's law constant to calculate the moles of barium
that is 1 mole = 6.02 x 10^23 atoms
? moles = 2.3 x 10^23 atoms
by cross multiplication
=(1 mole x 2.3x 10^23 atoms) / 6.02 x10^23 atoms)= 0.382 moles
mass is therefore = 137.3 g/mol x 0.382 mol = 52.4 ( answer c)
explanation: