_NaF + _Br2 →_NaBr + _F2

2NaF + 1Br2 -> 2NaBr + 1F2

Explanation:

2NaF + 1Br2 -> 2NaBr + 1F2

I simply looked at both the left side and right side and saw there was only 1 F on the left side while there were 2 on the right side.

This means we have to make the left side have 2 F by multiplying NaF by 2.

However, this means there are now 2 Na as well. Going back to the right side, I multiplied NaBr by 2 so that there are 2 Na on both sides.

Now there are 2 Br on the right side. Checking back to the left side, there are also 2 Br, meaning this equation is now balanced.

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

"hydrogen bonding is the attraction of h atoms in the water molecule (slight + charge) to o atoms in a neighboring water molecule (slight - charge); it is a weak interatomic force. but it is still strong enough to the water molecules "stick" together."