Calculate the change in temperature of a 650. g sample of water that loses 5480. J of energy

2

Explanation:

1) the formula of the energy is:

E=cm*Δt, where E - the value of the energy (5480 J.), c - the specific heat capacity (4200 J/(kg*C)), Δt - the difference between initial temperature and the final one (it is unknown);

2) if to perform the substitution of the values 'E', 'm' and 'c' into the formula above, then

5480=4200*0.65*Δt;

3) to calculate Δt:

Δt=5480/4200/0.65≈2 (°C).

note: the initial temperature is higher than the final.

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explanation:

58750.08068 is the answer i think