How many moles of H2 gas would be produced from the use of 8.5 moles of Al with excess of HCl? 1 point
J. 12 mol H2
K. 13 mol H2
L. 5.67 mol H2
M. 6 mol H2

yes

explanation:

search chemistry final b exam in google and a site called quizlet will pop up

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

it's 3.2 on edge, i just took the test.