Having difficulty understanding formulas involved. determine the quantity (g) of pure cacl2 in 7.5 g of cacl2•9h2o.

To determine the quantity of pure CaCl2 from the given amount of CaCl2.9H2O, we use the ratio of CaCl2 to CaCl2.9H2O. From the formula the ratio would 1 is to 1 We calculate as follows:

7.5 g CaCl2.9H2O (1 mol / 273.1215 g) ( 1 mol CaCl2 / 1 mol CaCl2.9H2O ) ( 110.98 g / 1 mol ) = 3.05 g CaCl2

Hope this answers the question. Have a nice day. Feel free to ask more questions.

Hchjxhkhsldncjkxkdğjxkfkjslcjdlkdşfnxjjd