NaCl +
Ba3(PO4)2
Na3PO4
+
BaCl2
1000 grams of sodium chloride is combined with 2000
grams of barium phosphate.
a)What is the limiting reactant?
b) How many grams of excess reactant are left?

a) Sodium Chloride is the limiting reactant.

b)285g of Ba3(PO4)2

Explanation:

a) 1000g Nacl x (1mol of Nacl/58.5g) x (2 Mol Na3PO4/6 mol of NaCl)= 5.70

- 2000g Ba3 (PO4)2 X 1 mol of Ba3 (PO4)2/601.9 x 2 mol of Na3PO4/1 mol of Ba3 (PO4)2= 6.65

Hence; NaCl is the limiting Reactant.

b) 1000g Nacl x (1mol of Nacl/58.5g) x 1 mol of Ba3 (PO4)2/ 6 mol of NaCl x601.9g/1 mol= 1715g  Ba3(PO4)2 USED.

2000g- 1715g=285g of Ba3(PO4)2 Left.

i think it is true since you can test the answer and can use observations to complete it.

b. is the answer hoped i