10) Calculate the energy change for the formation of LiCl(s) from its elements in their standard states and the following tabulated information: ? 1 Li(s) + 1/2 C12(s) — LiCl(s)
2 Li+(g) + Cl-(s) -- LiCl(s)
3 Li(s) — Li(g)
4 1/2 Cl2(g) - Cl(g)
5 Cl(g) + e- →Cl-(3) Li(g) → Lit(g) + e-
1-853 kJ/mol
2+159.4 kJ/mol
3+121.7 kJ/mol
4-348.6 kJ/mol
5+520.2 kJ/mol

A) +1305.7 kJ/mol
B) +296.9 kJ/mol
C) -400.3 kJ/mol
D) -627.2 kJ/mol

Adozen is 12, and your needing to calculate the weight of one medium egg, so i would do 21/12=1.75 per egg, and check your answer by doing 1.75 * 12= 21 : ) : ): ): ): ) i hoped i

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

The state or quality of being humid.a quantity representing the amount of water vapor in the atmosphere or a gas.