Answers: 1
), measured in joules, to convert ice at -50.0 ºC to liquid water at 0.0 ºC is the sum of sensible heat associated with ice and latent heat of fussion. That is:![Q = m\cdot [c\cdot (T_{f}-T_{o})+L_{f}]](/tpl/images/1099/9286/6f71d.png)
(1)
- Mass, measured in grams. 
- Specific heat of ice, measured in joules per gram-degree Celsius.
, 
- Temperature, measured in degrees Celsius.
- Latent heat of fussion, measured in joules per gram.
, 
, 
, 
and 
, then the amount of heat is: ![Q = (20\,g)\cdot \left\{\left(2.06\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot [0\,^{\circ}C-(-50\,^{\circ}C)]+334\,\frac{J}{g} \right\}](/tpl/images/1099/9286/c7074.png)
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How much heat is required to convert 20.0 g of ice at 50.0⁰C to liquid water at 0.0⁰C? The specific...
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