Calculate what will be the volume of 10.0 grams of
gaseous ammonia at STP?

13.22 L

Explanation:

Given data:

Volume of ammonia = ?

Mass of ammonia = 10.0 g

Temperature = standard = 273.15 K

Pressure = standard = standard = 1 atm

Solution:

First of all we will calculate the number of moles of ammonia.

Number of moles = mass/molar mass

Number of moles = 10.0 g/ 17 g/mol

Number of moles = 0.59 mol

one mole of any substance at standard temperature and pressure occupy 22.41 L . Thus, 0.59 moles of ammonia will occupy,

0.59 mol × 22.4 L / 1 mol

13.22 L

12.4L

Explanation:

mw NH3 18

1 mole = 22.4L

10g = 10/18 moles

the answer is the first option

explanation:

just googled it m8. not that hard

lol