How much energy is required to heat up a Styrofoam cup from 25oC to 40oC? The mass of the cup is 20 grams and the specific heat capacity of Styrofoam is 1.1 J/(g *oC).

Q = 440 J

Explanation:

Given data:

Heat required = ?

Initial temperature = 25°C

Final temperature = 40°C

Mass in gram  = 20 g

Specific heat capacity = 1.1 J/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 40°C - 20°C

ΔT = 20°C

Q = 20 g×1.1 J/g.°C × 20°C

Q = 440 J

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer