A gas pressure of 1.26 kPa and occupies a volume of 2.39 L, what will its new pressure be? Round to the nearest hundredth place.

2.45kPa

Explanation:

THIS IS A COMPLETE QUESTION

A gas pressure of 1.26 kPa and occupies a volume of 2.39 L, what will its new pressure be if the volume is 1.23L ? Round to the nearest hundredth place.

From Boyles law

P1 V1= P2V2

Where P1= initial pressure= 1.26 kPa

V1= initial volume= 2.39 L,

V2= final volume= 1.23L

P2= final pressure= ?

P1 V1= P2V2

P2= (P1 V1)/V2

= (1.26 × 2.39)/1.23

=2.45kPa

Hence, its new pressure is 2.45kPa

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied