H₂ (2)
→ H.
H₂(8)
+
2(g)
wer

The given question is incomplete. The complete question is:

In the chemical reaction: , with 8 grams of and 16 grams of and the reaction goes to completion, what is the excess reactant and how much of that would remain?

A) 6 grams of  

B) 7 grams of  

C) 8 grams of

D) 12 grams of

E) 14 grams of

A) 6 grams of

Explanation:

To calculate the moles :

According to stoichiometry :

1 moles of require 2 moles of

Thus 0.5 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

(4.0-1.0) = 3.0 moles of  are left unreacted

Mass of remained=

Thus 6.0 g of will remain.

diaria maybe go see a doctor about that