If you cooled 85g of water from 55c° to 2c°, what is the amount of heat lost

Q = - 18830.9 J

Explanation:

Given data:

Mass of water = 85 g

Initial temperature = 55°C

Final temperature = 2°C  

Amount of heat lost = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water 4.18 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 2°C - 55°C

ΔT = -53°C

Q = 85 g × 4.18 j/g.°C × -53°C

Q = - 18830.9 J

Negative sign shows that heat is released.

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

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explanation:

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