Determine the number of atoms of O in 58.3 moles of Na₂Cr₂O₇.

2457.58×10²³ atoms of oxygen

Explanation:

Given data:

Number of moles of Na₂Cr₂O₇ = 58.3 mol

Number of atoms of oxygen = ?

Solution:

First of all we will calculate the number of moles of oxygen in 58.3 moles of Na₂Cr₂O₇.

1 mole of Na₂Cr₂O₇ contain 7 moles of oxygen.

58.3 mol × 7 = 408.1 mol

Number of atoms of oxygen:

1 mole contain 6.022×10²³ atoms

408.1 mol × 6.022×10²³ atoms / 1 mol

2457.58×10²³ atoms

the correct answer would be d. hope this !

d

explanation: