If 4.5 moles of AlCl3 were made, how many moles of CuCl2 were used?

6.75 moles of CuCl₂ were used

Explanation:

Given data:

Number of moles of AlCl₃ formed = 4.5 mol

Number of moles of CuCl₂ used = ?

Solution:

Chemical equation:

3CuCl₂ + 2Al  →   2AlCl₃ + 3Cu

Now we will compare the moles of CuCl₂ and AlCl₃

               AlCl₃       :      CuCl₂

                   2         :        3

                 4.5        :      3/2×4.5 = 6.75

6.75 moles of CuCl₂ were used.

the volume increases