1. Use the data table below and the attached graph paper to plot the mass and volume of the 5 samples of the minerals galena below. Note: the resulting line you plot is the minerals density!
The graph paper is on the last page.
2. Calculate the density of samples 1-5 and place the value in the "density" column of the data
table below.
3. Answer the questions below
Sample
Size
Mass
Volume
Density
1
small
15 g
2 cm3
8 cm3
60 g
AN
120 g
16 cm3
480 g
64 cm3
5
large
750 g
100 cm
Questions

The answer is d because i just took the test

Because a model would make the investigation easier to understand

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.